io.extractFilename
Description
Get the filename segment only from a path string.
Parameters
fullPath
string
Return value
filename
string
Example
print(io.extractFilename("C:\\Some Folder\\Some Subfolder\\filename.txt"))
Comments
See also
io.extractPath
io.getSpecialFolderPath
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Generated on the 26 June 2024 at 22:01:29 (UK Time)